程序代写代做 graph There is a 10*10 km area covered by 100 BTSs, and the coverage of each BTS is 1 km*1 km. The area is further divided into 25 location areas (LAs), and the size of each LA is 2 km*2 km. There are 5,000 mobile users (MUs) in the area. The movement of each mobile user follows the random waypoint model. Initially, all the mobile users are uniformly distributed over the network. Once a mobile user crosses the boundary of the two LAs, the mobile user will update its location, which generates 800 Kbps network traffic. Assume that voice call arrivals of each mobile user follow a Poison distribution with the average arrival rate equal to 0.0125 call/second. The network traffic generated by the paging process is 60 Kbps* N (where N is the number of the BTS in an LA.).

There is a 10*10 km area covered by 100 BTSs, and the coverage of each BTS is 1 km*1 km. The area is further divided into 25 location areas (LAs), and the size of each LA is 2 km*2 km. There are 5,000 mobile users (MUs) in the area. The movement of each mobile user follows the random waypoint model. Initially, all the mobile users are uniformly distributed over the network. Once a mobile user crosses the boundary of the two LAs, the mobile user will update its location, which generates 800 Kbps network traffic. Assume that voice call arrivals of each mobile user follow a Poison distribution with the average arrival rate equal to 0.0125 call/second. The network traffic generated by the paging process is 60 Kbps* N (where N is the number of the BTS in an LA.).

• a) Please monitor the location update traffic and paging traffic generated in the network over 1 hour and draw the related graph. (45%)
• b) Please change the size of an LA to be 1 km*1 km, 3 km*3 km, and 5 km*5 km. Find the average location update traffic and paging traffic generated in the network in 1 hour. (45%)

有一个10 * 10 km的区域,由100个BTS覆盖,每个BTS的覆盖范围为1 km * 1 km。该区域进一步分为25个位置区域(LA),每个LA的大小为2 km * 2 km。该地区有5,000个移动用户(MU)。每个移动用户的移动遵循随机航点模型1。最初,所有移动用户都通过网络统一分布。一旦移动用户越过两个LA的边界,移动用户将更新其位置,从而产生800 Kbps的网络流量。假设每个移动用户的语音呼叫到达均遵循Poison分布,平均到达率等于0.0125个呼叫/秒。寻呼过程产生的网络流量为60 Kbps * N(其中N是LA中BTS的数量)。
a)请监控1个小时内网络中生成的位置更新流量和寻呼流量,并绘制相关图表。 (45%)
b)请将LA的大小更改为1 km * 1 km,3 km * 3 km和5 km * 5 km。查找在1小时内网络中生成的平均位置更新流量和寻呼流量。
(45%