COMP-273 Arith/Mem (1)
Slides From Patterson’s 61C
C/Assembler Arithmetic and Memory Access
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°C operators, operands
°Variables in Assembly: Registers
° Addition and Subtraction in Assembly °Memory Access in Assembly
COMP-273 Arith/Mem (2)
Slides From Patterson’s 61C
Review C Operators/Operands
°Operators:+,-,*, /,%(mod); •7/4==1, 7%4==3
° Operands:
• Variables: fahr, celsius
• Constants: 0, 1000, -17, 15.4
°Assignment Statement: Variable = expression
• Examples:
celsius = 5*(fahr-32)/9; a = b+c+d-e;
COMP-273 Arith/Mem (3)
Slides From Patterson’s 61C
Assembly Design: Key Concepts
°Assembly language is essentially directly supported in hardware, therefore …
°It is kept very simple!
• Limit on the type of operands
• Limit on the set operations that can be done to absolute minimum
– if an operation can be decomposed into a simpler operation, don’t include it
COMP-273 Arith/Mem (4)
Slides From Patterson’s 61C
Assembly Variables: Registers (1/3)
°Unlike HLL, assembly cannot use variables
• Why not? Keep Hardware Simple °Assembly Operands are registers
• limited number of special locations built directly into the hardware
• operations can only be performed on these!
°Benefit: Since registers are directly in hardware, they are very fast
COMP-273 Arith/Mem (5)
Slides From Patterson’s 61C
Assembly Variables: Registers (2/3)
°Drawback: Since registers are in hardware, there are a predetermined number of them
• Solution: MIPS code must be very carefully put together to efficiently use registers
°32 registers in MIPS
• Why 32? Smaller is faster
°Each MIPS register is 32 bits wide
• Groups of 32 bits called a word in MIPS
COMP-273 Arith/Mem (6)
Slides From Patterson’s 61C
Assembly Variables: Registers (3/3)
°Registers are numbered from 0 to 31 °Number references:
$0, $1, $2, … $30, $31
°By convention, each register also has a name to make it easier to code:
$16-$22è $s0-$s7 (correspond to C variables)
$8-$15 è $t0-$t7 (correspond to temporary variables)
°In general, use register names to make
your code more readable
COMP-273 Arith/Mem (7)
Slides From Patterson’s 61C
Comments in Assembly
°Another way to make your code more readable: comments!
°Hash (#) is used for MIPS comments
• anything from hash mark to end of line is
a comment and will be ignored °Note: Different from C.
• C comments have format /* comment */ , so they can span many lines
COMP-273 Arith/Mem (8)
Slides From Patterson’s 61C
Assembly Instructions
°In assembly language, each statement (called an Instruction), executes exactly one of a short list of simple commands
°Unlike C (and most other High Level Languages), where each line could represent multiple operations
COMP-273 Arith/Mem (9)
Slides From Patterson’s 61C
Addition and Subtraction (1/3)
°Syntax of Instructions: 1 2,3,4
1) operation by name
2) operand getting result (“destination”) 3) 1st operand for operation (“source1”) 4) 2nd operand for operation (“source2”)
°Syntax is rigid:
• 1 operator, 3 operands
• Why? Keep Hardware simple via regularity
COMP-273 Arith/Mem (10)
Slides From Patterson’s 61C
Addition and Subtraction (2/3)
° Addition in Assembly
• Example: add $s0,$s1,$s2 (in MIPS)
Equivalent to: a = b + c(in C) where registers $s0,$s1,$s2 are
associated with variables a, b, c
°Subtraction in Assembly
• Example: sub $s3,$s4,$s5 (in MIPS)
Equivalent to: d = e – f(in C) where registers $s3,$s4,$s5 are
associated with variables d, e, f
COMP-273 Arith/Mem (11)
Slides From Patterson’s 61C
Addition and Subtraction (3/3)
°How do the following C statement? a = b + c + d – e;
°Break into multiple instructions add $s0, $s1, $s2 # a = b + c add $s0, $s0, $s3 # a = a + d sub $s0, $s0, $s4 # a = a – e
°Notice: A single line of C may break up into several lines of MIPS.
°Notice: Everything after the hash mark on each line is ignored (comments)
COMP-273 Arith/Mem (12)
Slides From Patterson’s 61C
Immediates
°Immediates are numerical constants. °They appear often in code, so there
are special instructions for them.
°Add Immediate:
addi $s0,$s1,10 (in MIPS) f=g+10 (inC)
where registers $s0,$s1 are associated with variables f, g
° Syntax similar to add instruction, except that last argument is a number instead of a register.
COMP-273 Arith/Mem (13)
Slides From Patterson’s 61C
Register Zero
°One particular immediate, the number zero (0), appears very often in code.
° So we define register zero ($0 or $zero) to always have the value 0.
°Use this register, it’s very handy! add $6,$0,$5 # copy $5 to $6
°This register is defined in hardware, so an instruction like
addi $0,$0,5
will do nothing.
COMP-273 Arith/Mem (14)
Slides From Patterson’s 61C
Assembly Operands: Memory
°C variables map onto registers; what about large data structures like arrays?
°1 of 5 components of a computer: memory contains such data structures
°But MIPS arithmetic instructions only operate on registers, never directly on memory.
°Data transfer instructions transfer data between registers and memory:
• Memory to register
• Register to memory COMP-273 Arith/Mem (15)
Slides From Patterson’s 61C
Data Transfer: Memory to Reg (1/3)
°To transfer a word of data, we need to specify two things:
• Register: specify this by number (0 – 31) • Memory address: more difficult
– Thinkofmemoryasasingleone- dimensional array, so we can address it simply by supplying a pointer to a memory address.
– Othertimes,wewanttobeableto offset from this pointer.
COMP-273 Arith/Mem (16)
Slides From Patterson’s 61C
Data Transfer: Memory to Reg (2/3)
°To specify a memory address to copy from, specify two things:
• A register which contains a pointer to memory
• A numerical offset (in bytes)
°The desired memory address is the
sum of these two values. ° Example: 8($t0)
• specifies the memory address pointed to by the value in $t0, plus 8 bytes
COMP-273 Arith/Mem (17)
Slides From Patterson’s 61C
Data Transfer: Memory to Reg (3/3)
°Load Instruction Syntax: 1 2,3(4)
1) operation (instruction) name
2) register that will receive value
3) numerical offset in bytes
4) register containing pointer to memory
°Instruction Name:
•lw $t0,8($s0)
(Load Word, so load 32 bits or one word at a time from memory at address $s0 + 8)
COMP-273 Arith/Mem (18)
Slides From Patterson’s 61C
Data Transfer: Reg to Memory
°Also want to store value from a register into memory
°Store instruction syntax is identical to Load instruction syntax
°Instruction Name: sw $t0,8($s0)
(meaning Store Word, so 32 bits
or one word are stored at a time to memory at address $s0 + 8)
COMP-273 Arith/Mem (19)
Slides From Patterson’s 61C
Role of Registers vs. Memory
°What if more variables than registers? • Compiler tries to keep most frequently
used variable in registers
• Writing less common to memory: spilling
°Why not keep all variables in memory? • Smaller is faster:
registers are faster than memory • Registers more versatile:
– MIPS arithmetic instructions can read 2, operate on them, and write 1 per instruction
– MIPS data transfer only read or write 1 operand per instruction, and no operation
COMP-273 Arith/Mem (20)
Slides From Patterson’s 61C
Pointers v. Values
°Key Concept: A register can hold any 32-bit value. That value can be a (signed) int, an unsigned int, a pointer (memory address), etc.
°If you write lw $t2,0($t0)
then $t0 better contain a pointer
° What if you write add $t2,$t1,$t0 then $t0 and $t1
must contain?
COMP-273 Arith/Mem (21)
Slides From Patterson’s 61C
Addressing: Byte vs. word
°Every word in memory has an address, similar to an index in an array
°Early computers numbered words like C numbers elements of an array:
•Memory[0],Memory[1],Memory[2], … Called the “address” of a word
°Computers needed to access 8-bit bytes as well as words (4 bytes/word)
°Today machines address memory as bytes, hence word addresses differ by 4
•Memory[0], Memory[4], Memory[8], …
COMP-273 Arith/Mem (22)
Slides From Patterson’s 61C
Notes about Memory
°Pitfall: Forgetting that sequential word addresses in machines with byte addressing do not differ by 1.
• Many an assembly language programmer has toiled over errors made by assuming that the address of the next word can be found by incrementing the address in a register by 1 instead of by the word size in bytes.
• So remember that for both lw and sw, the
sum of the base address and the offset must be a multiple of 4 (to be word aligned)
COMP-273 Arith/Mem (23)
Slides From Patterson’s 61C
“And in Conclusion…” (1/2)
°In MIPS Assembly Language: • Registers replace C variables
• One Instruction (simple operation) per line • Simpler is Better
• Smaller is Faster
° Memory is byte-addressable, but lw and sw access one word at a time.
° A pointer (used by lw and sw) is just a memory address, so we can add to it or subtract from it (using offset).
COMP-273 Arith/Mem (24)
Slides From Patterson’s 61C
“And in Conclusion…”(2/2)
° : add, addi,
C Variables: $s0 – $s7 Temporary Variables: $t0 – $t9 Zero: $zero
COMP-273 Arith/Mem (25)
Slides From Patterson’s 61C
Bonus slide 0
Addition and Subtraction (4/4)
°How do we do this?
•f = (g + h) – (i + j);
°Use intermediate temporary register add $s0,$s1,$s2 # f = g + h add $t0,$s3,$s4 # t0 = i + j
# need to save i+j, but can’t use
# f, so use t0
sub $s0,$s0,$t0 # f=(g+h)-(i+j)
COMP-273 Arith/Mem (26)
Slides From Patterson’s 61C
Bonus slide 1
Data Transfer: Memory to Reg (4/4)
°Example: lw $t0,12($s0)
This instruction will take the pointer in $s0, add 12 bytes to it, and then load the
value from the memory pointed to by this calculated sum into register $t0
•$s0 is called the base register • 12 is called the offset
• offset is generally used in accessing
elements of array or structure: base reg
points to beginning of array or structure
COMP-273 Arith/Mem (27)
Slides From Patterson’s 61C
Bonus slide 2
Data Transfer: Reg to Memory (2/2)
°Example: sw $t0,12($s0)
This instruction will take the pointer in $s0, add 12 bytes to it, and then store the value from register $t0 into the memory address pointed to by the calculated sum
COMP-273 Arith/Mem (28)
Slides From Patterson’s 61C
Bonus slide: Compilation
° What offset in lw to select A[8] in C?
° 4×8=32 to select A[8]: byte v. word
°Compile by hand using registers: g = h + A[8];
• g: $s1, h: $s2, $s3:base address of A °1st transfer from memory to register:
lw $t0,32($s3) # $t0 gets A[8] • Add 32 to $s3 to select A[8], put into $t0
°Next add it to h and place in g
add $s1,$s2,$t0 # $s1 = h+A[8]
COMP-273 Arith/Mem (29)
Slides From Patterson’s 61C
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