程序代写代做代考 graph C CITY UNIVERSITY OF HONG KONG

CITY UNIVERSITY OF HONG KONG

Course Code & Title: EE6605

Complex Networks: Modeling, Dynamics and Control

Session: Semester A 2020/21

This is an open-book Test on Thursday October 22

Answer all questions

* Student Name: ______________________

* Student ID: _________________________

You have 60 minutes (8:00-9:00pm), plus 10 minutes to save your answers as pdf file and upload the pdf file to Canvas. Deadline for receiving your answer pdf file is 9:10pm

Answering this exam paper implies your acknowledgment of the Pledge for following the Rules on Academic Honesty:

 “I pledge that the answers in this examination are my own and that I will not seek or obtain an unfair advantage in producing these answers. Specifically,

• I will not plagiarize (copy without citation) from any source;
• I will not communicate or attempt to communicate with any other person during the examination; neither will I give or attempt to give assistance to another student taking the examination; and
• I will use only approved devices (e.g., calculators) and/or approved device models.
• I understand that any act of academic dishonesty can lead to disciplinary action.”

Answering this exam paper implies your acknowledgment of the Pledge for following the Rules on Academic Honesty:

 “I pledge that the answers in this examination are my own and that I will not seek or obtain an unfair advantage in producing these answers. Specifically,

• I will not plagiarize (copy without citation) from any source;
• I will not communicate or attempt to communicate with any other person during the examination; neither will I give or attempt to give assistance to another student taking the examination; and
• I will use only approved devices (e.g., calculators) and/or approved device models.
• I understand that any act of academic dishonesty can lead to disciplinary action.”

Question 1 [60 Marks] (Basic Concepts and Network Modelling)

Q-1.1 [10 Marks]

For the network shown in Figure Q1.1, compute (1.1a) and (1.1b):

(1.1a) [5 Marks]

(a1) [2 marks] Node-betweenness of Node C (no need to normalize)

Answer: B(C) = ________________

(a2) [3 marks] Edge-betweenness of Edge B-C (no need to normalize)

Answer: B(B-C) = ________________

A B C D E F G

Figure Q1.1

(1.1b) [5 Marks]

(b1) [2 marks] Average distance of Node A to all other nodes

Answer: L = _______________

(b2) [3 marks] Degree correlation of P(1,1), and of P(1,2).

Answer: P(1,1) = _______________ P(1,2) = _________________

Q-1.2 [10 Marks]

(1.2a) [5 Marks] Consider the following network model:

• Step 1 (Initialization) Start with an undirected large-sized fully-connected network.
• Step 2 (Process) Pick up an edge: if removing it does not disconnect the whole network, then remove it; but if removing it will disconnect the network, then do nothing. Continue to pick up another edge from the resultant network and repeat the above possible edge-removal operation.
• Step 3 (End) After every possible edge has been operated once, and once only, stop.

(a1) [2 marks] What kind of network will you obtain?

Answer:

(a2) [3 marks] If the initial large-sized fully-connected network is directed, what is your conclusion?

Answer:

(1.2b) [5 Marks] Consider Figure Q1.2, where Node 2 sends 2 emails to all its neighbours (i.e., Nodes 1, 3, 4), with the following events:

Node 1 accepts the first email but rejects the second.
Node 3 rejects the first email but accepts the second.
Node 4 accepts both emails.

Calculate the weight

Answer: = ______________

Figure Q1.2

Q-1.3 [10 Marks]
Consider the graph shown in Figure Q1.3. Find:

Figure Q1.3

(1.3a) [2 marks] the coreness of the network
Answer: coreness = _________________
(1.3b) [2 marks] the clustering coefficient of any inner node
Answer: C(in) = ______________
(1.3c) [2 marks] the clustering coefficient of any outer node
Answer: C(out) = ______________
(1.3d) [2 marks] the length of girth of any inner node
Answer: g(in) = ________________
(1.3e) [2 marks] the length of girth of any outer node
Answer: g(out) = _________________

Q-1.4 [10 Marks]

Are the two graphs in Figure Q1.4 isomorphic? Show your reasoning.

Figure Q1.4

Answer: Yes: u1 – v1, u2 – v?, u3 – v?, u4 – v?, u5 – v?, u6 – v?, u7 – v?, u8 -v?

Or: No: Because _______________________

Q-1.5 [10 Marks]
Given a network with nodes.

(1.5a) [5 marks] If the network is undirected, with average degree . How many edges does this network have?

Answer: ____________________

(1.5b) [5 marks] If the network is directed, with average out-degree . How many directed edges does this network have?

Answer: ____________________

Q-1.6 [10 Marks] Consider the 6 graphs shown in Figure Q1.6.

Answer each question (type your answers like: A), C), F), …, etc.)

(1.6a) [2 marks] Eulerian graph(s): Answer: ______________

(1.6b) [2 marks] Semi-Eulerian graph(s): Answer: ______________

(1.6c) [2 marks] Hamiltonian graph(s): Answer: ______________

(1.6d) [2 marks] Semi-Hamiltonian graph(s): Answer: _____________

(1.6e) [2 marks] Neither Eulerian nor Hamiltonian graph(s): Answer: ______

Figure Q1.6

Question 2 [40 Marks] (Applications)

Q2.1 [20 Marks] Consider the traffic network shown in Figure Q2.1. (For this question, no need to draw pictures, and no need to show calculation steps.)

(2.1a) [15 marks] Show a spanning tree with the shortest total path length (type your answer like: connecting edges 1–3, 3–6, … )

Answer: Connecting edges ______________ and the total path length L = ___

(2.1b) [5 marks] Based on the above answer, find a path from Node 1 to Node 8 with the shortest total path length (type your answer like: The path is 1–>3–>6–> … –>8)

Answer: The path is _____________ and the total path length L = ___

Figure Q2.1

Q2.2 [20 Marks] Solve the Chinese Postman Problem shown in Figure Q2.2 (type your answer like: Add edges 1-4, 4-3, 2-4, …, etc.). Show numerical comparison of all possible choices. (For this question, no need to compute the total basic time T, which is not useful.)

Figure Q2.2

Answer:

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