CS计算机代考程序代写 Fourth One

Fourth One
C

In rdt 3.0 if sender reacts to second ACK for the same packet by re-transmission of the data
packet this packet will be processed by the receiver and passed to the application.

(L/R)/(RTT+(L/R)) [3:37 PM] L = 1000 bits = 125 bytes RTT = 10ms = 0.01s R = 125000
bytes/s 125/125000 = 0.001s 0.001 / (0.01 + 0.001) = 0.0909090909

I think its 40 [2:21 PM]

65-25 [2:21 PM]
not sure
[2:21 PM]
nobody told me

it’s in slides

Seqnew = ackprevious Acknew = seqprevious + 1 201, 14 should be the answer

After reaching the threshold value, New Reno enters into the congestion avoidance phase
and, to overcome this fault, it resets its congestion window to half of the ssthresh (Slow
Start Threshold) value and then it increases its CWND size by one each RTT, which results
in degrading the performance and utilization of Link.
Slow start phase ends when congestion window reaches value of ssthresh variable.

20000-500*35 = 2500 2500/500 = 5

ANSWER: 0.8N