CS计算机代考程序代写 Bayesian flex case study Lecture 3. Linear Regression. Optimisation.

Lecture 3. Linear Regression. Optimisation.
COMP90051 Statistical Machine Learning
Semester 2, 2019 Lecturer: Ben Rubinstein
Copyright: University of Melbourne

COMP90051 Statistical Machine Learning
This lecture
• Linearregression
∗ Simple model (convenient maths at expense of flexibility)
∗ Often needs less data, “interpretable”, lifts to non-linear
∗ Derivable under all Statistical Schools: Lect 2 case study • Today: Frequentist + Decision theory derivations
Later in semester: Bayesian approach
• Optimisation for ML (first of 2 parts or so) ∗ Analytic solutions
∗ Gradient descent ∗ Convexity
Later: Lagrangian duality
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COMP90051 Statistical Machine Learning
Linear Regression via Decision Theory
A warm-up example
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COMP90051 Statistical Machine Learning
Example: Predict humidity from temperature
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In regression, the task is to predict numeric response (aka dependent variable) from features (aka predictors or independent variables)
Assume a linear relation: 𝐻𝐻 = 𝑎𝑎 + 𝑏𝑏𝑏𝑏
(𝐻𝐻 – humidity; 𝑏𝑏 – temperature; 𝑎𝑎, 𝑏𝑏 – parameters)
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Temperature
Humidity
TRAINING DATA
85
85
80
90
83
86
70
96
68
80
65
70
64
65
72
95
69
70
75
80
TEST DATA
75
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COMP90051 Statistical Machine Learning
Example: Problem statement
• The model is 𝐻𝐻 = 𝑎𝑎 + 𝑏𝑏𝑏𝑏
• Fitting the model = finding “best” 𝑎𝑎, 𝑏𝑏 values for data at hand
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• Popular criterion: minimise the sum of squared errors (aka residual sum of squares)
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COMP90051 Statistical Machine Learning
Example: Minimise Sum Squared Errors
Tofind𝑎𝑎,𝑏𝑏thatminimise𝐿𝐿=∑10 𝐻𝐻 − 𝑎𝑎+𝑏𝑏𝑏𝑏 𝜕𝜕𝐿𝐿 10 𝑖𝑖=1𝑖𝑖 𝑖𝑖
2 =−2� 𝐻𝐻−𝑎𝑎−𝑏𝑏𝑏𝑏=0
set derivatives to zero:
𝜕𝜕𝑎𝑎
𝑖𝑖=1
𝑖𝑖𝑖𝑖
High-school optimisation: • Write derivative
• Set to zero
• Solve for model
• (Check 2nd derivatives) Will cover again later
1 ∑10 𝐻𝐻 − 𝑏𝑏 𝑏𝑏 𝜕𝜕𝐿𝐿 10 10 𝑖𝑖=1 𝑖𝑖 𝑖𝑖
if we know 𝑏𝑏, then 𝑎𝑎� =
𝜕𝜕𝑏𝑏=−2�𝑖𝑖=1𝑏𝑏𝑖𝑖 𝐻𝐻𝑖𝑖−𝑎𝑎−𝑏𝑏𝑏𝑏𝑖𝑖 =0
if we know 𝑎𝑎, then 𝑏𝑏� = 1 2 ∑10 𝑏𝑏𝑖𝑖 𝐻𝐻𝑖𝑖 − 𝑎𝑎 ∑10 𝑇𝑇 𝑖𝑖=1
𝑖𝑖=1
𝑖𝑖
Can we be more systematic?
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COMP90051 Statistical Machine Learning
Example: Analytic solution
• Wehavetwoequationsandtwounknowns𝑎𝑎,𝑏𝑏 • Rewriteasasystemoflinearequations
10 𝑖𝑖 = 10 𝑖𝑖 10 ∑ 𝑏𝑏 𝑎𝑎 ∑ 𝐻𝐻
𝑖𝑖=1 𝑏𝑏 𝑖𝑖=1
∑10 𝑏𝑏 ∑10 𝑏𝑏2 ∑10 𝑏𝑏𝐻𝐻 𝑖𝑖=1 𝑖𝑖 𝑖𝑖=1 𝑖𝑖 𝑖𝑖=1 𝑖𝑖 𝑖𝑖
• Analyticsolution:𝑎𝑎=25.3,𝑏𝑏=0.77
• (Solveusingnumpy.linalg.solveorsim.)
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COMP90051 Statistical Machine Learning


Here 𝑤𝑤1, … , 𝑤𝑤𝑚𝑚 ∈ R denote weights (model parameters) Trick: add a dummy feature 𝑥𝑥0 = 1 and use vector
More general decision rule
Adopt a linear relationship between response 𝑦𝑦 ∈ R and an instance with features 𝑥𝑥1, … , 𝑥𝑥𝑚𝑚 ∈ R
notation 𝑚𝑚
𝑦𝑦 � = �𝑖𝑖 = 0 𝑥𝑥 𝑖𝑖 𝑤𝑤 𝑖𝑖 = 𝒙𝒙 ′ 𝒘𝒘
𝑚𝑚
𝑦𝑦 � = 𝑤𝑤 0 + �𝑖𝑖 = 1 𝑥𝑥 𝑖𝑖 𝑤𝑤 𝑖𝑖
A lowercase symbol in bold face indicates a vector; 𝒙𝒙′ denotes transpose 8

COMP90051 Statistical Machine Learning
Linear Regression
via Frequentist Probabilistic Model
Max Likelihood Estimation
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COMP90051 Statistical Machine Learning
Data is noisy!
Example: predict mark for Statistical Machine Learning (SML) from mark for Knowledge Technologies (KT)
Training data*
KT mark
KT mark
* synthetic data 🙂
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SML mark
SML mark

COMP90051 Statistical Machine Learning
𝑦𝑦 Regression as a probabilistic model
𝑥𝑥
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• Assume a probabilistic model: 𝑌𝑌 = 𝑿𝑿′𝒘𝒘 + 𝜀𝜀
∗ Here𝑿𝑿,𝑌𝑌and𝜀𝜀arer.v.’s ∗ Variable𝜀𝜀encodesnoise
𝜀𝜀~𝒩𝒩 0,𝜎𝜎
• Next, assume Gaussian noise (indep. of X):
• Recall that 𝒩𝒩 𝑥𝑥; 𝜇𝜇, 𝜎𝜎2 ≡ 1 exp − 𝑥𝑥−𝜇𝜇 2 2𝜋𝜋𝜎𝜎2 2𝜎𝜎2
this is a squared error!
•Therefore𝑝𝑝 2𝑦𝑦|𝒙𝒙= 1 exp−𝑦𝑦−𝒙𝒙′𝒘𝒘2 𝒘𝒘,𝜎𝜎 2𝜋𝜋𝜎𝜎2 2𝜎𝜎2
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COMP90051 Statistical Machine Learning
Parametric probabilistic model

𝑦𝑦
Using simplified notation, discriminative
model is:
𝑝𝑝 𝑦𝑦|𝒙𝒙 = 1 exp − 𝑦𝑦−𝒙𝒙′𝒘𝒘 2
𝑥𝑥
2𝜎𝜎2 • Given observed data { 𝑿𝑿1,𝑌𝑌1 ,…, 𝑿𝑿𝑛𝑛,𝑌𝑌𝑛𝑛 }, we want to find

2𝜋𝜋𝜎𝜎2
Unknown parameters: 𝒘𝒘, 𝜎𝜎2
parameter values that “best” explain the data
• Maximum likelihood estimation: choose parameter values that maximise the probability of observed data
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COMP90051 Statistical Machine Learning
Maximum likelihood estimation
𝑛𝑛
𝑝𝑝 𝑦𝑦1,…,𝑦𝑦𝑛𝑛|𝒙𝒙1,…,𝒙𝒙𝑛𝑛 = �𝑖𝑖=1 𝑝𝑝 𝑦𝑦𝑖𝑖|𝒙𝒙𝒊𝒊
• Assuming independence of data points, the probability of data is
•For𝑝𝑝𝑦𝑦𝑖𝑖|𝒙𝒙𝑖𝑖=1 exp−𝑦𝑦𝑖𝑖−𝒙𝒙𝑖𝑖′𝒘𝒘2 2𝜋𝜋𝜎𝜎2 2𝜎𝜎2
• “Log trick”: Instead of maximisin1g this quantity, we can maximise its logarithm (why?)
𝑛𝑛𝑛𝑛
�𝑖𝑖=1log𝑝𝑝𝑦𝑦𝑖𝑖|𝒙𝒙𝒊𝒊 =−2𝜎𝜎2�𝑖𝑖=1 𝑦𝑦𝑖𝑖−𝒙𝒙𝑖𝑖′𝒘𝒘2+𝐶𝐶
here 𝐶𝐶 doesn’t depend on 𝒘𝒘 (it’s a constant)
the sum of squared errors!
• Under this model, maximising log-likelihood as a function of 𝒘𝒘 is equivalent to minimising the sum of squared errors
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COMP90051 Statistical Machine Learning
Non-linear Continuous Optimisation
Brief summary of a few basic optimisation methods vital for ML
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COMP90051 Statistical Machine Learning
Optimisation formulations in ML
• Training = Fitti�ng = Parameter estimation
• Typicalformulation
𝜽𝜽∈argmin𝐿𝐿 𝑑𝑑𝑎𝑎𝑑𝑑𝑎𝑎,𝜽𝜽
𝜽𝜽∈Θ
∗ argmin because we want a minimiser not the minimum • Note: argmin can return a set (minimiser not always unique!)
∗ Θ denotes a model family (including constraints)
∗ L denotes some objective function to be optimised • E.g.MLE:(conditional)likelihood
• E.g. Decision theory: (regularised) empirical risk
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COMP90051 Statistical Machine Learning
Two solution approaches
• Analytic(akaclosedform)solution
∗ Known only in limited number of cases
𝜕𝜕𝜕𝜕 = ⋯ = 𝜕𝜕𝜕𝜕 = 0 𝜕𝜕𝜃𝜃1 𝜕𝜕𝜃𝜃𝑝𝑝
∗ Use 1st-order necessary condition for optimality*:
• Approximate iterative solution
1. Initialisation:�choose starting guess 𝜽𝜽 , set 𝑖𝑖 = 1
2. Update: 𝜽𝜽(𝑖𝑖+1) ← 𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆𝑆 𝜽𝜽(𝑖𝑖) , set 𝑖𝑖 ← 𝑖𝑖 + 1
3. Termination: decide whether to Stop
4. GotoStep2
5. Stop: return 𝜽𝜽 ≈ 𝜽𝜽(𝑖𝑖)
(1)
* Note: to check for local minimum, need positive 2nd derivative (or Hessian positive definite); this assumes unconstrained – in general need to also check boundaries. See also Lagrangian techniques later in subject.
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Assuming unconstrained, differentiable L

COMP90051 Statistical Machine Learning
Finding the deepest point
𝜃𝜃2
𝜃𝜃1
• In this example, a model has 2 parameters
• Each location corresponds to a particular combination of parameter values
• Depth indicates objective value (e.g. loss) of that candidate model on data
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COMP90051 Statistical Machine Learning
• Suppose𝜽𝜽= 𝜃𝜃1,…,𝜃𝜃𝐾𝐾 2. For𝑖𝑖from1to𝑏𝑏 (*)
′ 1. Choose 𝜽𝜽(1) and some 𝑏𝑏
Coordinate descent
1. 𝜽𝜽(𝑖𝑖+1) ← 𝜽𝜽(𝑖𝑖)
2. For𝑗𝑗from1to𝐾𝐾
𝜃𝜃2
1. Fix components of 𝜽𝜽(𝑖𝑖+1), except 𝑗𝑗-th component
2. Find 𝜃𝜃� 𝑖𝑖+1 that minimises 𝑗𝑗 𝑖𝑖+1
𝐿𝐿𝜃𝜃𝑗𝑗
3. Up�date 𝑗𝑗-th component of 𝜽𝜽(𝑖𝑖+1)
3. Return 𝜽𝜽 ≈ 𝜽𝜽(𝑖𝑖)
*Other stopping criteria can be used
𝜃𝜃1
Wikimedia Commons. Author: Nicoguaro (CC4) 18

COMP90051 Statistical Machine Learning
Reminder: The gradient
• Gradient at 𝜽𝜽 defined as 𝜕𝜕𝜕𝜕 ,…, 𝜕𝜕𝜕𝜕 ′ evaluated at 𝜽𝜽
• Thegradientpointstothedirectionofmaximal change of 𝐿𝐿(𝜽𝜽) when departing from point 𝜽𝜽
𝜕𝜕𝜃𝜃1 𝜕𝜕𝜃𝜃𝑝𝑝
• Shorthandnotation
∗ 𝛁𝛁𝐿𝐿 ≝ 𝜕𝜕𝜕𝜕 , … , 𝜕𝜕𝜕𝜕 ′ computed at point 𝜽𝜽
𝜕𝜕𝜃𝜃1 𝜕𝜕𝜃𝜃𝑝𝑝
∗ Here 𝛁𝛁 is the “nabla” symbol
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COMP90051 Statistical Machine Learning
Gradient descent 1. Choose 𝜽𝜽(1) and some 𝑏𝑏
Assuming 𝐿𝐿 is differentiable
2. For𝑖𝑖from1to𝑏𝑏*
3.
• •
1. 𝜽𝜽(𝑖𝑖+1) = 𝜽𝜽(𝑖𝑖) − 𝜂𝜂𝛁𝛁𝐿𝐿(𝜽𝜽(𝑖𝑖)) Return 𝜽𝜽� ≈ 𝜽𝜽(𝑖𝑖)
Note: 𝜂𝜂 is dynamically updated in each step
Variants: Stochastic GD, Mini batches, Momentum, AdaGrad, ….
𝜽𝜽(0)
*Other stopping criteria can be used
Wikimedia Commons. Authors: Olegalexandrov, Zerodamage
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COMP90051 Statistical Machine Learning
Convex objective functions • ‘Bowl shaped’ functions
𝑤𝑤2
• Informally: if line segment between any two points on graph of function lies above or on graph
• Formally* 𝑓𝑓: 𝐷𝐷 → 𝐑𝐑 is convex if∀𝒂𝒂,𝒃𝒃∈𝐷𝐷,𝑑𝑑∈ 0,1:
𝑓𝑓𝑑𝑑𝒂𝒂+ 1−𝑑𝑑𝒃𝒃 ≤𝑑𝑑𝑓𝑓𝒂𝒂 + 1−𝑑𝑑𝑓𝑓𝒃𝒃 Strictly convex if inequality is strict (<) 𝑤𝑤1 • Gradient descent on (strictly) convex function guaranteed to find a (unique) global minimum! * Aside: Equivalently we can look to the second derivative. For f defined on scalars, it should be non-negative; for multivariate f, the Hessian matrix should be positive semi-definite (see linear algebra supplemental deck). 21 COMP90051 Statistical Machine Learning L1 and L2 norms • Throughout the course we will often encounter norms that are functions R𝑛𝑛 → R of a particular form ∗ Intuitively, norms measure lengths of vectors in some sense ∗ Often component of objectives or stopping criteria in optimisation-for-ML 𝒂𝒂=𝒂𝒂≡𝑎𝑎+⋯+𝑎𝑎 2 122 𝑛𝑛2 • More specifically, we will often use the L norm (aka Euclidean distance) 𝒂𝒂≡𝑎𝑎+⋯+𝑎𝑎 11𝑛𝑛 • And also the L norm (aka absolute norm or Manhattan distance) 1 • For example, the sum of squared errors is a squared norm 𝑛𝑛𝑚𝑚 𝐿𝐿 = � 𝑖𝑖 = 1 𝑦𝑦 𝑖𝑖 − �𝑗𝑗 = 0 𝑋𝑋 𝑖𝑖 𝑗𝑗 𝑤𝑤 𝑗𝑗 2 = 𝒚𝒚 − 𝑿𝑿 𝒘𝒘 2 22 COMP90051 Statistical Machine Learning ...And much much more • What if you have constraints? • What about speed of convergence? • Is there anything faster than gradient descent (yes, but can be expensive) • Do you really need differentiable objectives? (no) • Are there more tricks? (hell yeah!) We’ll see Lagrangian duality later on Free at http://web.stanford.edu/~boyd/cvxbook/ 23 COMP90051 Statistical Machine Learning One we’ve seen: Log trick • Instead of optimising 𝐿𝐿 𝜃𝜃 , try convenient log 𝐿𝐿(𝜃𝜃) • Strictly monotonic function: a > 𝑏𝑏 ⟹ 𝑓𝑓 𝑎𝑎 > 𝑓𝑓(𝑏𝑏) ∗ Example: log function!
• Whyareweallowedtodothis?
• Lemma: Consider any objective function 𝐿𝐿 𝜃𝜃 and any strictly monotonic f. 𝜃𝜃∗ is an optimiser of 𝐿𝐿 𝜃𝜃 if and only if it is an optimiser of 𝑓𝑓(𝐿𝐿 𝜃𝜃 ).
∗ Proof: Try it at home for fun!
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COMP90051 Statistical Machine Learning
Linear Regression Optimisation
For either MLE/decision-theoretic derivations
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COMP90051 Statistical Machine Learning
Method of least squares
Analytic solution:
• Write derivative • Set to zero
• Solve for model
• Training data: { 𝒙𝒙1,𝑦𝑦1 ,…, 𝒙𝒙𝑛𝑛,𝑦𝑦𝑛𝑛 }. Note bold face in 𝒙𝒙𝑖𝑖
• For convenience, place instances in rows (so attributes go in columns),
representing training data as an 𝑛𝑛 × (𝑆𝑆 + 1) matrix 𝑿𝑿, and 𝑛𝑛 vector 𝒚𝒚 • Probabilistic model/decision rule assumes 𝒚𝒚 ≈ 𝑿𝑿𝒘𝒘
• To find 𝒘𝒘, minimise the sum of squared errors 𝑛𝑛𝑚𝑚
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𝐿𝐿=�𝑖𝑖=1 𝑦𝑦𝑖𝑖−�𝑗𝑗=0𝑋𝑋𝑖𝑖𝑗𝑗𝑤𝑤𝑗𝑗
• Setting derivative to zero and solving for 𝒘𝒘 yields 𝒘𝒘� = 𝑿𝑿 ′ 𝑿𝑿 − 1 𝑿𝑿 ′ 𝒚𝒚
∗ This system of equations called the normal equations ∗ System is well defined only if the inverse exists
In this slide: UPPERCASE symbol in bold face means matrix; 𝑿𝑿′ denotes transpose; 𝑿𝑿−1 denotes matrix inverse 26

COMP90051 Statistical Machine Learning
Wherefore art thou: Bayesian derivation?
• Later in the semester: return of linear regression • FullyBayesian,withaposterior:
∗ Bayesian linear regression
• Bayesian (MAP) point estimate of weight vector: ∗ Adds a penalty term to sum of squared losses
∗ Equivalent to L2 “regularisation” to be covered soon! ∗ Called: ridge regression
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COMP90051 Statistical Machine Learning
Summary
• Linearregression
∗ Probabilistic frequentist derivation
∗ Decision-theoretic frequentist derivation
Later in semester: Bayesian approaches • OptimisationforML
Next time:
logistic regression – linear probabilistic model for classification; basis expansion for non-linear extensions
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