CS计算机代考程序代写 Haskell — CPSC 312 – 2021 – Games in Haskell

— CPSC 312 – 2021 – Games in Haskell
module Minimax where

— To run it, try:
— ghci
— :load Minimax

import MagicSum
–import CountGame

—- Determining the best move —
minimax:: Game -> State -> (Action, Double)
— minimax game state => (move,value_to_player)
— precondition: there are some moves that are available
minimax game st =
argmax (valueact game st) avail
where State _ avail = st

— valueact game st action is the value of doing action act in state st for game
valueact:: Game -> State -> Action -> Double
valueact game st act = value game (game act st)

— value gameminimax magicsum result = value for current player after result
value:: Game -> Result -> Double
value _ (EndOfGame val _) = val
value game (ContinueGame st) = – snd (minimax game st) — (action,value) for next player
— value for current player is negative of value of the other player

— to find the best opening move
— minimax magicsum magicsum_start

–Try (for MagicSum)
as lst = [Action i | i <- lst] -- make it easier to type -- minimax magicsum (State (as [8,5,4], as [1,2,6,9]) (as [3,7])) -- minimax magicsum (State (as [8,5], as [1,2]) (as [3,4,6,7,9])) -- minimax magicsum (State (as [1,2], as [4,5,8]) (as [3,6,7,9])) -- minimax magicsum (State (as [4,5,8], as [1,2,9]) (as [3,6,7])) -- minimax magicsum (State (as [1,2,4,5], as [3,7,8,9]) (as [6])) -- minimax magicsum (State (as [1,2,4,5], as [3,6,8,9]) (as [7])) -- minimax magicsum (State (as [1,2,5], as [3,6,8,9]) (as [4,7])) -- minimax magicsum (State (as [1,5], as [3,8]) (as [2,4,6,7,9])) -- minimax magicsum (State (as [1], as [5,8]) (as [2,3,4,6,7,9])) -- minimax magicsum (State (as [5,8], as [1,2]) (as [3,4,6,7,9])) -- minimax magicsum (State (as [5], as [3,8]) (as [1,2,4,6,7,9])) -- minimax magicsum (State ([], []) (as [1..9])) mm_player:: Game -> Player
mm_player game state = fst ( minimax game state)

— argmax f lst = (e, f e) for e <- lsts where f e is maximal -- Precondition: lst is not empty -- Note that this does not require the elements of lst to be comparable, only value -- like max[(e,f e) <- e in lst] but where only the second elements of pairs are compared in the max. argmax :: Ord v => (e -> v) -> [e] -> (e,v)
argmax f [e] = (e, f e)
argmax f (h:t)
| fh > ft = (h,fh)
| otherwise = (bt, ft)
where
(bt,ft) = argmax f t
fh = f h

— after surfing the web, I found this is the standard argmaxWithMax
— http://hackage.haskell.org/package/list-extras-0.4.1.4/docs/Data-List-Extras-Argmax.html

— Test case:
— argmax (\x -> 5- (x-2)^2) [0..10]
— argmax (\x -> 1 + 4*x – x^2) [0..10]

— another implementation
argmax2 :: Ord v => (e -> v) -> [e] -> (e,v)
argmax2 f (h:t) =
foldr (\ e (et,vt) -> let fe = f e in
if (fe > vt) then (e,fe) else (et,vt))
(h, f h) t