程序代写代做代考 x86 Java c++ data structure Buffer Overflow

Buffer Overflow

Buffer Overflow

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A simple function
void f() {
int i;
int buf[9];

for (i=0; i < 5; i++) buf[4+i] = buf[4-i] = 0; } ‹#› A simple function void f() { int i; int buf[9]; for (i=0; i < 10; i++) buf[4+i] = buf[4-i] = 0; } ‹#› The call stack A data structure that stores information about function calls in a program In X86 the stack is bottom-up The stack bottom is at a high address The stack top is at a low address The stack grows towards lower addresses Bottom of stack Top of stack ‹#› Implementation Register %esp points to the top of the stack The push instruction pushes a value onto the stack xorl %eax,%eax pushl %eax pop pops a value popl %eax %esp 0 %esp ‹#› Calling a function Calling a function pushes a stack frame onto the stack The stack base pointer register (%ebp) points to the frame of the current function Return pops the stack frame Stack frame %esp %ebp ‹#› Calling conventions Caller does: Save registers Push arguments Call function Callee does Save %ebp Set new %ebp Create space for local variables Caller’s stack frame %esp %ebp Saved Registers Arguments Return address Saved %ebp Local Variables %esp %esp %esp %esp %esp %ebp %esp, %ebp ‹#› Example int g(int a, int b) { int x = a + 1; int y = b + 2; return x*y; } g: pushl %ebp movl %esp, %ebp subl $16, %esp movl 8(%ebp), %eax addl $1, %eax movl %eax, -8(%ebp) movl 12(%ebp), %eax addl $2, %eax movl %eax, -4(%ebp) movl -8(%ebp), %eax imull -4(%ebp), %eax leave ret b a Return address Saved %ebp y x %ebp %esp %esp %esp %ebp %esp, %ebp %esp ‹#› Back to a simple function void f() { int i; char buf[9]; for (i=0; i < 10; i++) buf[4+i] = buf[4-i] = 0; } i 0 0 buf 1 0 0 0 2 0 0 0 0 0 3 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Saved %ebp Return address ‹#› 0 5 i buf Saved %ebp Return address 1 5 5 2 5 5 3 5 5 4 5 5 With a minor change void f() { int i; char buf[9]; for (i=0; i < 10; i++) buf[4+i] = buf[4-i] = 5; } 5 5 5 5 6 5 5 7 ‹#› buf Stack smashing void f() { char buf[512]; gets(buf); doSomething(buf); } The attacker diverts execution to data it injected How does the attacker know where to jump to? Caller’s stack frame Return address Saved %ebp gets stack frame buf buf Return address Saved %ebp Caller’s stack frame ‹#› NOP Sled A sequence of NOP instructions leading to the attack code NOP NOP NOP . . . NOP NOP Attack Code ‹#› Problem patterns Any use of gets strcpy, sprintf, strcat, etc. sprintf(buf, "https://%s/index.html", argv[1]) buf=new char[strlen(argv[1])] strcpy(buf, argv[1]) wchar_t buf[MAXLEN]; swprintf(buf, sizeof(buf), "%s", argv[1]); Any low-level implementation of similar code while (*src != ';') *dst++ = *src++; *dst = '\0'; ‹#› Avoiding buffer overflows Do not use gets. Replace unsafe C string functions with safe version Redefine unsafe functions to catch use, for example: char *strcpy(char *dst, const char *src) { fprintf(stderr, "Don't use strcpy\n"); abort(); } May fail if library functions use strcpy Replace C strings with safe(r) C++ strings ‹#› Avoiding buffer overflows - 2 Abstract over array access to include bounds checking For example, use the C++ vector .at() method What about performance? Code reviews and audits. Use static code analysis tools Switch to Java, C#, etc. ‹#› Non-executable stacks The stack is only used for data. There’s no need to run code from the stack The memory management unit can prevent code execution based on the address Only protects against branching back to the stack Does not prevent: Heap overflow Return Oriented Programming buf Caller’s stack frame Return address Saved %ebp gets stack frame buf buf Return address Saved %ebp Caller’s stack frame ‹#› ROP Illustrated ‹#› StackGuard On function entry, callee Saves %ebp Sets new %ebp Pushes the canary Creates space for local variables Verify the canary on function exit The attacker has to overwrite the canary before changing the return address There are ways around the canary Does not protect from heap overflows, changing function pointers, etc. Caller’s stack frame Saved Registers Arguments Return address Saved %ebp Local Variables Canary ‹#› STack Overwrite Protection Push a large buffer to the stack at process initialisation The attacker does not know how to set the return address A large enough NOP-sled has a non-negligible probability of a success Only protects the stack ASLR (Address Space Layout Randomization) extends protection to the heap and to libraries buf Return address Saved %ebp buf buf Return address Saved %ebp buf buf Return address Saved %ebp buf ‹#› Summary Buffer overflow is a common vulnerability Good coding practices often prevent overflows There are some systematic defence mechanisms There’s no silver bullet ‹#›