代写代考 Lecture 30,

Lecture 30,

of regular conv .

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MA : 111007211101£
(7001-1100)
11100%11012
7,708, 101
1100+1099-1
1101) + 1101 (5901) =

gun, } → n=o
-1-1=-1-19-47
tien,} n=o
# complex MAS = 3.(NlogzN)-1N
13 ) + 8192 = 327,680
MAs=4327,680)= 1,310,720
FFT fewer than 20%
⇒ approach
standard c o n n
where a ,b,
and C a re complex

Blockconvqfu.fi#
Given {xinifn and {him}^ , N >> M , n=0
segme.int/onginput-*
Let✗k(e)= ✗(KL+d) 0<-1EL- 1-, 1<=91,2... ✗(n)= ⇐✗K In- KL) , 0 Next, Con. . is a linear operator ycn)= hcn) * ✗(n)= hint* !Xkcn - KL) = [ hen) * XK (n - KL (n ) = hen) * ✗KG) overlapandttnd 1)Pad {×,CS代考 加微信: powcoder QQ: 1823890830 Email: powcoder@163.com