CS 7638: Artificial Intelligence for Robotics
Warehouse Project – Fall 2022 – Deadline: Monday November 14th, Midnight AOE
Introduction
In this project, you will implement search algorithms to navigate a robot through a warehouse to pick up and deliver boxes to a designated drop zone area. The template code provides 3 classes, one for each part of the project: DeliveryPlanner_Part[A, B, C]
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• You may share code between part A, B, and C
• Your submission will consist of a single file: warehouse.py
• The weighting for each part is: – PartA=40%
– PartB=40%
– PartC=20%
• Within each part, each test case is equally weighted.
• Part A and B have opportunities for extra credit. Any extra credit earned in these parts will supplement
lost points in another part. The overall max score for this project is 101% (1% extra credit).
Part A (40%)
Your task is to pick up and deliver all boxes listed in the todo list. You will do this by providing a list of motions that the testing suite will execute in order to complete all the deliveries. Your algorithm should determine the best path to take when completing this task.
DeliveryPlanner_PartA’s constructor must take five arguments: self, warehouse, robot_position, todo, and box_locations. It must also have a method called plan_delivery that takes 2 arguments: self and debug (set to False by default).
Part A Input Specifications
warehouse will be a custom object used by the testing suite. For all intents and purposes, you can think of it as a list of m lists, each inner list containing n characters, corresponding to the layout of the warehouse. The warehouse is an m x n grid. warehouse[i][j] corresponds to the spot in the ith row and jth column of the warehouse, where the 0th row is the northern end of the warehouse and the 0th column is the western end.
NOTE: In part A, your code will not know (nor should it depend on) the size of the warehouse (n and m). You are only allowed to use the warehouse object (WarehouseAccess) in the following 2 ways, if we find
that your code is using any other methods/approaches to use or manipulate the warehouse object, you will receive a 0 for part A (this may be done manually after the project is due):
1. You may access a particular cell in the warehouse using warehouse[i][j]
2. You may overwrite the contents of a cell using warehouse[i][j] = ‘
is only for your convenience if needed)
The goal in part A is to not only find an optimal path to the goal, but to do so in an efficient manner. Efficiency here means that your algorithm should access (view) as few of the warehouse cells as possible. Accessing a particular cell more than once will not hurt you as we will only tally the unique cells that your algorithm accesses each test case. It is your responsibility to make sure you are not using any other way to glean information from the warehouse other than the 2 methods above. There are some precautions in place to help notify you when you are improperly using the warehouse object, however, these are not exhaustive. A few things to ask yourself (if you answer yes to any of these, you are likely approaching the problem incorrectly and likely going to receive a 0 for this part):
1. Are you attempting to determine the size of the warehouse?
2. Are you attempting to access an entire row of the warehouse (rather than a particular cell)?
3. Are you accessing a private attribute (as indicated by a leading underscore) of the warehouse?
4. Are you iterating through the warehouse in any way?
5. Are you somehow gaining access to a warehouse cell’s contents without it being counted towards the
viewed_cell_count?
6. Are you attempting to copy the warehouse object/data in any way?
The characters in each string will be one of the following:
. (period) : traversable space. The robot may enter from any adjacent space.
# (hash) : a wall. The robot cannot enter this space. All warehouse cases will be surrounded by walls.
@ (dropzone) : the starting point for the robot and the space where all boxes must be delivered. The dropzone
may be traversed like a . (period).
[0-9a-zA-Z] (any alphanumeric character) : a box. At most one of each alphanumeric character will be present in the warehouse (meaning there will be at most 62 boxes). A box may not be traversed, but if the robot is adjacent to the box, the robot can pick up the box. Once the box has been lifted, the space that the lifted box previously occupied now functions as a . (period).
For example,
warehouse = [‘#####’,
is a 5×5 warehouse.
• The dropzone is at the warehouse cell in row 3, column 3.
• Box 1 is located in the warehouse cell in row 1, column 1.
• Box 2 is located in the warehouse cell in row 1, column 3.
• There are walls within the warehouse at cells (row 1, column 2) and (row 2, column 2) and around the
warehouse.
• The remaining five warehouse cells (which includes the dropzone) are traversable spaces.
The argument todo is a list of alphanumeric characters giving the order in which the boxes must be delivered to the dropzone. For example, if todo = [‘1′,’2’] is given with the above example warehouse, then the robot must first deliver box 1 to the dropzone, and then the robot must deliver box 2 to the dropzone.
Part A Rules & Costs for Motions
• The robot may move in 8 directions (N, E, S, W, NE, NW, SE, SW)
• The robot may not move outside the warehouse. The warehouse does not “wrap” around (it is not
• Two spaces are considered adjacent if they share an edge or a corner.
• The robot may pick up a box that is in an adjacent square.
• The robot may put a box down in an adjacent square, so long as the adjacent square is empty (. or @).
• While holding a box, the robot may not pick up another box.
• There are 4 kinds of motions that the robot can take:
– [cost]: type
– [ 2 ]: horizontal or vertical movement
– [ 3 ]: diagonal movement
– [ 4 ]: pick up box (regardless the direction)
– [ 2 ]: put down box (regardless the direction)
• If a box is placed on the @ space, it is considered delivered and is removed from the warehouse, thus the @ space is still traversable after dropping a box on it.
• The warehouse will be arranged so that it is always possible for the robot to move to the next box on the todo list without having to rearrange any other boxes.
• The robot will end up in the same location when an illegal motion is performed.
• An illegal motion will incur a penalty cost of 100 in addition to the motion cost.
• Illegal motions include:
– attempting to move to a nonadjacent, nonexistent, or occupied space
– attempting to pick up a nonadjacent or nonexistent box
– attempting to pick up a box while already holding one (attempting to put down a box while not
holding one)
– attempting to put down a box on a nonadjacent, nonexistent, or occupied space (this means the
robot may not drop a box on the drop zone while the robot is occupying the drop zone)
Part A Method Return Specifications
plan_delivery should return a list of moves that minimizes the total cost of completing the task. Each move should be a string formatted as follows:
• ‘move {d}’, where ‘{d}’ is replaced by the direction the robot should move: “n”, “e”, “s”, “w”, “ne”, “se”, “nw”, “sw”
• ‘lift {x}’, where ‘{x}’ is replaced by the alphanumeric character of the box being picked up
• ‘down {d}’, where ‘{d}’ is replaced by the direction the robot will put the box down
For example, for the values of warehouse and todo given previously (reproduced below):
warehouse = [‘#####’,
todo = [‘1′,’2’]
plan_delivery might return the following:
[‘move w’,
‘move nw’,
‘move se’,
‘move ne’,
Part A Scoring
The testing suite will execute your plan and calculate the total cost: student_cost. The score for each test case will be calculated by: benchmark_cost / student_cost. The benchmark will be greater than or equal to the absolute minimum cost, which leaves an opportunity for extra credit on some test cases. You will receive a 0 in the following situations:
• your code views more warehouse cells than specified in the test case: viewed_cell_count_threshold • your code takes longer than the prescribed time limit
• your method returns the wrong output format
• the boxes are not delivered in the correct order
Part B (40%)
In this part there are three main differences from part A:
• there will be only a single box for your robot to deliver
• the warehouse has an “uneven” floor which imposes an additional cost (range: 0 ~ 95 inclusive) • the robot starting location is not provided
DeliveryPlanner_PartB’s constructor must have four arguments: self, warehouse, warehouse_cost, and todo.
Part B Input Specifications
Same as part A but the only box in the warehouse will be: 1 (the single box to be delivered).
Note: Test cases in the test suite will only contain the characters listed in part A’s input Specifications section. There is a helper function (_set_initial_state_from) that parses this initial input into an internal warehouse state. This is the same internal state representation that is used by the testing suite. You are NOT required to use this helper function and may change it as you see fit, it is just provided for convenience. Note that the testing suite uses an asterisk (*) to denote the current location of the robot as it executes your plan. This asterisk is only used for internal purposes in the testing suite so you will not see it present in the test cases. It is also used to denote the robot’s location in some examples in this document.
For example:
warehouse = [‘1..’,
The argument warehouse_cost is a list of lists such that indices i,j refer to the floor cost at the row i and column j in the warehouse. For the case above, the corresponding warehouse_cost could be:
warehouse_cost = [[ 0, 5, 2],
[10, w, 2],
[ 2, 10, 2]]
where w represents a wall. Note that the value of w has no consequence since the robot can’t occupy a space
containing a wall.
The argument todo is limited to a single box as follows:
todo = [‘1’]
There is no input for initial robot location because the robot may “wake up” at any point in the warehouse and must be handed a “policy” so that no matter where it is, it can retrieve the box. Further, because it may
lift the box from different squares depending on its starting location, it requires another “policy” to deliver the box to the dropzone.
• Note: You must update your internal warehouse state in your code as this is not done for you.
Part B Rules for Motions
Same as part A.
Part B Costs for Actions
The total cost for an action consists of a summation of 2 parts:
• motion cost (same as part A) • floor cost
– movements: value of the destination cell the robot is moving into – lift: value of the cell the box is located in prior to lifting
– down: value of the cell the box is being placed into
This means although you may incur less motion cost to move straight to a target location, the additional floor cost along the way may be such that taking a roundabout way will result in an overall lower cost.
For example the lowest cost route to box 1 is not [‘move e’, ‘move e’]:
warehouse = [‘*..1’,
warehouse_cost = [[ 1, 95, 50, 1],
[ 1, 1, 1, 1],
[ 1, w, w, 1],]
Two example calculations for the total cost of an action using the example grid above are:
• If the robot enters (0,1) from (0,0) then the total action cost will be:
total action cost = motion cost (horizontal movement) + floor cost (destination) =2 +95=97.
• If the robot enters (0,1) from (1,0) then the total action cost will be:
total action cost = motion cost (diagonal movement) + floor cost (destination) =3 +95=98.
Note that the floor cost to move into cell (0,1) is 95 regardless of the direction the robot is entering from. Three example calculations for the total action cost of illegal motions (i.e. attempting to move into (or
put down a box at) an occupied space or outside the warehouse) are:
• If the robot attempts to move east from (2,0) then the total action cost will be:
total action cost = motion cost (horizontal movement) + illegal motion penalty cost = 2 + 100 = 102.
• If the robot attempts to move southeast from (2,0) then the total action cost will be:
total action cost = motion cost (diagonal movement) + illegal motion penalty cost = 3 + 100 = 103.
• If the robot attempts to put down a box to the southeast from (2,0) then the total action cost will be: total action cost = motion cost (put down box) + illegal motion penalty cost
= 2 + 100 = 102.
Note that the motion costs are still included in the case of illegal motions even though they weren’t successful (the robot still exerted the energy). Floor costs are only incurred when a motion is legally carried out. Floor costs (of the box location) are incurred when legally lifting/putting down boxes.
Part B Method Return Specifications
plan_delivery should return two policies, each as a list of lists of strings indicating the motion to take at each square on the grid. The format of the commands is the same as in part A. The special command
‘-1’ should be placed at any square for which there is no valid command, such as a wall.
For example, for the values of warehouse and todo given previously (reproduced below):
warehouse = [‘1..’,
plan_delivery might return the following two policies:
To Box Policy:
[[‘B’ , ‘lift 1’ , ‘move w’ ]
[‘lift 1’, ‘-1’ , ‘move nw’]
[‘move n’, ‘move nw’, ‘move n’ ]]
Deliver Box Policy:
[[‘move e’ , ‘move se’, ‘move s’]
[‘move ne’, ‘-1’ , ‘down s’]
[‘move e’ , ‘down e’ , ‘move n’]]
where: ‘B’ indicates the box location.
For the “Deliver Box Policy”, the dropzone includes a motion in the event the robot starts on, lifts an adjacent box, and then must move off the dropzone to deliver it.
Part B Scoring
The testing suite will pick a starting location for the robot and then execute the motions specified by the “To Box Policy” until it finds and lifts the box. Then it will use the “Deliver Box Policy” and, given the location of the robot when it lifted the box, the appropriate commands are executed until the the box is delivered to the dropzone. The total cost of the student delivery is denoted as: student_cost. The score for each test case will be calculated the same as part A.
Part C (20%)
In this part there is only one main difference from part B: • move motions are stochastic
DeliveryPlanner_PartC’s constructor must have five arguments: self, warehouse, warehouse_cost, todo, and stochastic_probs.
In part A and B we dealt with a deterministic robot. In real life however, we are inevitably faced with stochasticity. As such, part C is about finding an optimal policy based on stochastic robot motions.
Note: For this part you should find 2 individually optimal policies: pick up and drop off. This means your main algorithm should be executed 2 times: once to obtain the optimal policy to pick up the box and once to obtain the optimal policy to deliver the box.
Part C Rules for Motions
Rules for motions are almost the same as part A & B. Instead of deterministic movements however, the robot will move according to a probability distribution defined by stochastic_probabilities. stochastic_probabilities will give you the probability that the movement will be as_intended, slanted, or sideways as depicted in the grids below. Since these are probabilities, the sum of all possible outcomes will be one: 2 ∗ (sideways + slanted) + as_intended = 1. Your code should be able to handle any distribution
provided to you in stochastic_probabilities. as_intended will be strictly greater than 0% and strictly less than 100%. The as_intended direction in the images below indicates the intended movement by the robot. Note that slanted and sideways are with respect to the intended movement direction.
Example #1 Example #2 Example #3
Note that Example 2 and 3 above are the same since orientation does not matter in this project, they are both provided to emphasize that the unintended stochastic outcomes are with respect to the intended movement direction.
To understand the stochastic movement probability better, lets take a look at a few concrete examples. Assume the movement probability distribution is given as:
• as intended = 70% • slanted = 10%
• sideways = 5%
Do yourself a favor and validate that the sum of all possible outcomes for this example is indeed one. The probability distribution showing the outcomes of an intended movement of “move n” in 3 different scenarios are depicted below:
Example #4 Example #5 Example #6
Notice that in example #5, the two locations occupied by a wall prevent the robot from moving into those spaces and therefore the robot stays in place 15% (10% + 5% ) of the time. Similarly, any attempt to move outside the warehouse will result in the robot staying in the same location (as seen in example #6).
Only directional movement is stochastic. The lift and down motions are deterministic. 7
Part C Costs for Actions
Same as part B, with the clarification that the cost incurred is the cost of the motion actually performed.
This may differ from the motion attempted (intended), due to the stochastic nature of Part C.
For example, if the intended motion is a vertical movement, but the robot ends up performing a slanted movement then the result will incur a diagonal movement cost. Similarly, if the intended motion is a diagonal movement, but the robot ends up performing a sideways movement then the result will incur a diagonal movement cost.
Part C Output Specifications
Same as part B.
Part C Scoring
TL;DR: for each correct policy (to-box and to-dropzone) you will earn 0.5 points for a total of 1 point per test case. More details about the scoring are below, but not required to complete the project. There is no extra credit for this part.
A random number generator will be seeded in order to produce deterministic (consistent) results. The testing suite will initialize a robot at robot_init. The student policy is then used to express the intended motion at each step. The performed motion (stochastic movement or deterministic lift/down) is recorded at each step. Note that the performed motion may not be the same as the motion specified in your policy (intended motion) due to stochasticity. The list of performed motions (actions) are recorded as: student_performed_actions. Since the random number generator is seeded, a particular policy will always produce the same list of performed motions. You are given 0.5 points if student_performed_actions match the correct_performed_actions.
Before starting the to-zone policy procedure, the testing suite will place the robot at location robot_init2 and pick up the box. This is to allow you partial credit to earn points for a correct to-dropzone policy even if you failed the to-box policy.
Note that there is very little information that can be gleaned from analyzing correct_performed_actions. This is not intended as a means of debugging for the students, rather as a way to grade the policy. This means you aren’t given a crutch that tells you exactly what your code should be outputting, instead you must analyze your code by scrutinizing your implementation of the algorithm and making sure to adhere to the warehouse rules laid out in this document.
Environment Test
Before changing warehouse.py, test your environment using the following steps: 1) From the command line run: python warehouse.py
• A list of moves for Part A test case 1 should be printed
• A “to_box_policy” and “deliver_policy” will be printed for part B, test case 1
• A “to_box_policy” and “to-zone_policy” will be printed for part C, test case 1 2) From the com
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