代写代考 EE99:

TI‐83 normal lookup example
• Tofindnormalcdf()
– Press 2nd and then“DISTR” buttons – Scroll to normalcdf or press “2”

Copyright By PowCoder代写 加微信 powcoder

TI‐83 normal lookup example • ForP(x6000) =1 – P(d<6000) = 1 ‐ normalcdf(‐EE99,6000,4500,900) = 0.04779 • To use the standard normal z directly, only 2 inputs: 1 ‐ P(z<1.67) would be = 1 ‐ normalcdf(‐EE99,1.67) = 0.04779 Minus “infinity” TI‐83 binomial lookup example • For P(x = r) with n trials and p given: • Use binompdf(n,p,x) • For n=3, r=1, p=.50 use binompdf(3,.5,1) • press 2nd VARS [DISTR], ARROW DOWN to select 0:binompdf(, and then press ENTER • Enter the values separated by commas and the closing “)” then enter. 程序代写 CS代考 加微信: powcoder QQ: 1823890830 Email: powcoder@163.com